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  1. #41

  2. #42
    Senior Member KaosPenguin's Avatar
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    Old enough to know better, young enough not to care.

  3. #43
    Member Dlusion's Avatar
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    Let sin 2x = k

    k = 22- 8√7

    k - 22 = -8√7 [Bring 22 to the LHS)

    (k-22)² = (-8√7)² [Squaring both sides]

    k² - 44k + 484 = 448 [Expanding]

    k² - 44k = 448-484 [Bringing 484 to the RHS]

    k² - 44k = -36 [Multiply throughout by k]

    k³ - 44k² = -36k

    k³ - 44k² + 36k = 0 [Bringing -36k to the LHS]

    k³ - 49k² +5k² + 8k + 28k = 0 [Rearranging factors]

    k³ + 5k² + 8k = 49k² - 28k [Rearranging factors and bring 49k² - 28k to the RHS]

    k³ + 4k² + k² + 4k + 4k = 49k² - 28k [Rearranging factors]

    k³ + 4k² + k² + 4k + 4k + 4 - 4 = 49k² - 28k [Adding + 4 and -4 to make it a quadratic/polynomial]

    k³ + 4k² + k² + 4k + 4k + 4 = 49k² - 28k + 4 [Bringing -4 to the RHS]

    k³ + 4k² + k² + 4k + 4k + 4 = (7k - 2)² [Writing 49k² - 28k + 4 in the form of (a-b)²]

    (1+k)(k² + 4k + 4) = (7k - 2)² [Factoring LHS]

    (1+k)(k + 2)² = (7k - 2)² [Writing k² + 4k + 4 in the form of (a+b)²]

    (1+k) = (7k-2)²/(k+2)² [Bringing (k+2)² to the RHS]

    (1 + 2sinxcosx) = (7k-2)²/(k+2)² [k = sin2x = 2sinxcosx]

    (sin²x + cos²x + 2sinxcosx) = (7k-2)²/(k+2)² [ 1 = sin²x + cos²x and we bring LHS to the form (a+b)²]

    (sinx + cosx)² = (7k-2)²/(k+2)²

    (sinx + cosx) = (7k-2)/(k+2) [Taking root on both sides]

    sinx + cosx = (7k -2)/k / (k+2)/k) [Divide Numerator and Denominator of RHS by k]

    sinx + cosx = (7 - 2/k) / (1+2/k)

    (sinx + cosx) (1 + 2/k) = 7 - 2/k [Taking (1+2/k) to the LHS]

    sinx + cosx + 2sinx/k + 2cosx/k = 7 - 2/k [Multiplying and Expanding]

    sinx + cosx + 2/k(sinx + cosx) + 2/k = 7 [Taking Common factor out]

    sinx + cosx + 2/k(sinx + cosx + 1) = 7 [Taking Common factor out]

    sinx + cosx + 2/k(sinx + cosx + sin²x + cos²x) = 7 [ 1 = sin²x + cos²x]

    sinx + cosx + 2/2sinxcos (sinx + cosx + sin²x + cos²x) = 7 [k = sin2x = 2sinxcosx]

    sinx + cosx + 1/cosx + 1/sinx + sinx/cosx + cosx/sinx = 7 [Canceling common terms]

    sinx+cosx+secx+cosecx+tanx+cotx = 7 [1/cosx=secx,1/sinx=cosecx,sinx/cosx=tan…

    Therefore sinx + cosx + secx + cosecx + tanx + cotx = 7

    3(sinx + cosx + secx + cosecx + tanx + cotx) = My age.
    <a href=http://i.imgur.com/rtpizaH.jpg target=_blank>http://i.imgur.com/rtpizaH.jpg</a>

  4. #44
    Senior Member Protonix's Avatar
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    So you're 21.

    Child's play.

  5. #45
    Senior Member A s0t's Avatar
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    Quote Originally Posted by Protonix View Post
    So you're 21.

    Child's play.
    you forgot to divide by Zero
    worker bees can leave
    even drones can fly away
    the queen is their slave--Fight Club

    Joshua: A strange game. The only winning move is not to play.

    http://www.etaew.net/defiance/
    http://www.defiance.com/en/game/?CAS...oMEGHvtLge-cas

  6. #46
    Senior Member Protonix's Avatar
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    Nonsense.!

  7. #47
    Member Dlusion's Avatar
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    Quote Originally Posted by Dlusion View Post
    Therefore sinx + cosx + secx + cosecx + tanx + cotx = 7

    3(sinx + cosx + secx + cosecx + tanx + cotx) = My age.
    Is what makes it child's play =] GG
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  8. #48
    Senior Member Tenz's Avatar
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    Im 26 i think... i honestly dont recall at the moment how strange...


    EDIT: i was right 26 LOL
    The only thing set in stone is your birth, the rest of your destiny lay in your hands - Tenz
    Xbox360 Gamer Tag: L0RDT3NZ
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    Alpha CHaracter: Tenz

    Looking for 360 Guild in PST zone, currently in beta and alpha so friend to play with would be nice PM please if you want to play.

  9. #49
    Senior Member Far_Too_Jones's Avatar
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    25 til I'm 30 and I'm 30 in October.
    To a New Yorker like you, a hero is some type of weird sandwich, not some nut who takes on three tigers.

  10. #50
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    Quote Originally Posted by Tenz View Post
    Im 26 i think... i honestly dont recall at the moment how strange...


    EDIT: i was right 26 LOL
    Are you a po/thead?

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